Question

"Professor Offenrokker has a solution that is 6.0 x 10-3 M of HCl of a solution. However, he needs 450 mL of a 6.0 x 10-4 M HCl solution. How much of the stock solution will he need to make the dilute solution?"

Answer 1

Answer : The volume of the stock solution he need to make the dilute solution will be, 45 mL

Explanation :

According to dilution dilution law:

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of concentrated solution

`M_2` = molarity of dilute solution

`V_1` = volume of concentrated solution

`V_2` = volume of dilute solution

Given:

`M_1` =
`6.0* 10^(-3)M`

`M_2` =
`6.0* 10^(-4)M`

`V_1` = ?

`V_2` = 450 mL

Now put all the given values in the above formula, we get:

`(6.0* 10^(-3)M)* V_1=(6.0* 10^(-4)M)* 450mL`

`V_1=45mL`

Therefore, the volume of the stock solution he need to make the dilute solution will be, 45 mL