Question

Find the exact values of sin 2θ and cos 2θ for sin θ= 5/11 on the interval 0° ≤ θ ≤ 90°

pls help asap!

Answer 1

Below in bold.

Explanation:

sin ^2x + cos ^2 x = 1, so

cos^2x = 1 - (5/11)^2 = 96/121

cos x = √96/11

= 4√6/11.

sin 2x = 2 sinx cosx = 2 * 5/11 * 4√6/11.

= 40√6/121.

cos2x = 2cos^2 x - 1

= 2 * 96/121 - 1

= 192/121 - 121/121

= 71/121.