Question

A ball is released from a height of 18 m and weighs 19 N . What is the magnitude of the total change in potential energy Δ U as the ball falls to the ground?

Answer 1

The magnitude of the total change in potential energy ΔU as the ball falls to the ground is 342 joules.

Step-by-step explanation:

It is given that,

Height from which the ball is released, h = 8 m

Weight of the ball, F = 19 N

To find,

The magnitude of the total change in potential energy ΔU as the ball falls to the ground.

Solution,

The energy that is possessed by an object due to its position is called its potential energy. Its formula is given by :

`\Delta U=mgh`

`\Delta U=F* h`

`\Delta U=19\ N* 18\ m`

`\Delta U=342\ J`

So, the magnitude of the total change in potential energy ΔU as the ball falls to the ground is 342 joules. Hence, this is the required solution.