Question

30pointsssss

Use graphs and tables to find the limit and identify any vertical asymptotes of the function.

limit of 1 divided by the quantity x minus 1 squared as x approaches 1

Answer 1

Vertical asymptote at x=1

Explanation:

We find out limit approaches from right first

Since the denominator is a positive quantity because it has square

We find out limit approaches from right

The limit would be infinity

To find out vertical asymotote , we take the denominator and set it =0

(x-1)^2=0

Take the squares on both sides

(x-1) = 0

Add 1 on both sides

x=1

Vertical asymptote at x=1

Hope this helps.