Answer:
![(4x)/(2x+y) +(2y)/(2x+y)=2](https://img.qammunity.org/2021/formulas/mathematics/high-school/dni0ttruqdfpif4u7nijczu9xaiuaghru8.png)
Explanation:
Given:
The expression to simplify is given as:
![(4x)/(2x+y) +(2y)/(2x+y)](https://img.qammunity.org/2021/formulas/mathematics/high-school/7csuze8mzks5ibs83m5gj5tz9wqtpi2v2j.png)
Since, the denominator is same, we add the numerators and divide it by the same denominator. This gives,
![(4x+2y)/(2x+y)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3q422jrolk2d9duk51rqcwqkis8xkikqax.png)
Now, we simplify further by factoring out the common terms from the numerator and denominator if possible.
We observe that, 2 is a common factor to both
. So, we factor out 2 from the numerator. This gives,
![(2(2x+y))/(2x+y)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d7b7ogq5klxsk4c25e91e4hyizllnsooqy.png)
Now, the term
is common in both the numerator and denominator. Hence,
![(2x+y)/(2x+y)=1](https://img.qammunity.org/2021/formulas/mathematics/high-school/3u7w6br446etriagefthqvvnbq4poswuy3.png)
So, the simplified form is:
![=2* (2x+y)/(2x+y)\\\\=2* 1\\\\=2](https://img.qammunity.org/2021/formulas/mathematics/high-school/46lrj3w7tlhyp87l6ds91zwz9k7e4vgtjs.png)