1 Answer

Ask a Question

Twyla · Answer 1 · 2021-02-24T12:52:39+0000

Answer:

$1.73553* 10^(-10)\ m$

Step-by-step explanation:

h = Planck's constant =
$6.626* 10^(-34)\ m^2kg/s$

K = Potential difference = 50 V

m = Mass of electron =
$9.11* 10^(-31)\ kg$

The de broglie wavelength is given by

$\lambda=(h)/(√(2mK))\\\Rightarrow \lambda=\frac{6.626* 10^(-34)}{\sqrt{2* 9.11* 10^(-31)* 50* 1.6* 10^(-19)}}\\\Rightarrow \lambda=1.73553* 10^(-10)\ m$

The wavelength is
$1.73553* 10^(-10)\ m$

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Other Questions