Question

A piece of paper in the shape of an equilateral triangle with side length 3 and a circular piece of paper with radius 1 are glued together so that their centers coincide. How long is the outer perimeter of the resulting 2-dimensional shape?

Answer 1

6+pi or 9.14

Explanation:

Answer 2

Outer perimeter of the resulting 2-dimensional shape will be 18.84 units

Explanation:

From the figure, we could see

AE = FB = 1

And minor arc EF

=>
`(2 \pi (1) )/(6)`

=>
`= (2 \pi)/( 6)`

=>
`= ( \pi)/( 3)`

So by symmetry the perimeter is

=>
`3(2 + \frac { \pi}{3} )`

=>
`3(\frac {6 \pi}{3} )`

=>
`6 \pi`

=>
`6 * 3.14`

=> 18.84 units