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A student uses pens whose lifetime is an exponential random variable with mean 1 week. Use the central limit theorem to determine the minimum number of pens he should buy at the beginning of a 15-week semester, so that with probability .99 he does not run out of pens during the semester.

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Answer:

Student needs pens= n = 27.04

Rounding off with upper floor function ⇒ n =28

Rounding off with lower floor function ⇒ n =27

Explanation:

Given that lifetime of each pen is a exponential random variable with mean 1 week.

Let
S_(n) be total sum of lifetime of n pens.

So mean of
S_(n) = μ = n.1

Standard deviation of
S_(n) =
\sigma=√(n)

Probability that he doesnot run out of pens= 0.99

Considering Sn be sum of n lifetimes, using central limit theorem


(S_(n)-n)/(√(n))\approx N(0,1)\\\\P(S_(n)>15)=[P((S_(n)-n)/(√(n)))>(15-n)/(√(n))]\\ 1-\phi((15-n)/(√(n)))=\phi(-((15-n)/(√(n))))=0.99\\

From table of standard normal distribution


(15-n)/(√(n))=-2.3263\\15-n=-2.3263√(n)\\n-2.3263-15√(n)

Solving the quadratic Equation in variable x we get

n=27.04

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