Question

A device plugged into a wall outlet experiences an alternating current. The RMS current value is 2 A. The peak current is ___.

Answer 1

The peak value of current will be 2.828 A.

Step-by-step explanation:

Given that

Value of RMS current I(rms) = 2 A

Lets take peak current = I(p)

As we know that relationship between RMS and peak current given as

`I(rms)=(I(p))/(\sqrt2)`

Now by putting the values in the above equation

`I(rms)=(I(p))/(\sqrt2)`

`2\ A=(I(p))/(\sqrt2)`

`I(p)=2\sqrt2`

As we know that

`√(2)=1.414`

Therefore

I(p)=2.828 A

The peak value of current will be 2.828 A.