Answer:
let x = number of cheap cards
y = number of expensive cards
x + y = 24 ( equation 1 )
(1)(x) + (3)(y) = 50
x + 3y = 50 ( equation 2 )
equation 2 - equation 1
(x + 3y) - ( x + y ) = 50 - 24
x + 3y - x -y = 26
2y = 26
y = 26/2
y = 13 expensive cards
x + y = 24
x + 13 = 24
x = 24 -13
x = 11 cheap cards
verification :
x + 3y = 50
11 + 3(13) = 50
11 + 39 = 50
50 = 50
correct.
the final answer
11 cheap cards
13 expensive cards