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A circle has its center at (0,0) and passes through the point (0,9). What is the standard equation of the circle? x² + y² = 0 x² + y² = 9 x² + y² = 9²

A circle has its center at (0,0) and passes through the point (0,9). What is the standard equation of the circle? x² + y² = 0 x² + y² = 9 x² + y² = 9²
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A circle has its center at (0,0) and passes through the point (0,9). What is the standard equation of the circle?

x² + y² = 0


x² + y² = 9


x² + y² = 9²

User MarkusEgle
by
7.5k points

1 Answer

4 votes

Answer:

Explanation:

I believe the answer is x² + y² = 9²

User Ankit Kumar Gupta
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