Answer:
The motion of the parachute = 3.3 m/s²
Step-by-step explanation:
Weight of the parachute - Resistive force of air = ma
W - Fₐ = ma.................... Equation 1
making a the subject of formula in equation 1
a = (W- Fₐ)/m.................. Equation 2
Where W = weight of the parachute, Fₐ = resistive force of air, m = mass of the parachute, a = acceleration of the parachute
Constant: g = 9.8 m/s²
Given: Fₐ = 520 N, m = 80 kg
W = mg = 80 × 9.8 = 784 N,
Substituting these values into equation 2
a = (784-520)/80
a = 264/80
a = 3.3 m/s²
Therefore the motion of the parachute = 3.3 m/s²