Question

A spring that is stretched 23 cm from its equilibrium point experiences a force of 103 N .Now much force is stored in the spring?

Answer 1

given,

spring is stretched = 23 cm

x = 0.23 m

Force experiences = 103 N

we know,

F = k x

where k is the spring constant

`k =(F)/(x)`

`k =(103)/(0.23)`

k = 447.83 N/m

Assuming we have to calculate the energy stored in the spring

energy stored in the spring

`U =(1)/(2)kx^2`

`U =(1)/(2)* 447.83 * 0.23^2`

U = 11.85 J

hence, energy stored in the spring is equal to U = 11.85 J