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Prove that if f : A → B, g : B → C, and g ◦ f is injective , then f : A injective

User Willw
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Answer:

Check it down.

Explanation:

Injective functions or One to one functions are functions in each one element of A set is is mapped to another element of B set

1) Let's start by listing supposition and their respective Reasons

Suppose:


g\circ f is injective then
f:A\rightarrow B is also injective.

Reason: Given

2) Since we are dealing with injective (one to one) functions, we can rightly proceed:


f(x)=f(y) \:such \:as\: x,y \in A


g(f(x))=g(f(y))

Given the fact that
g\circ f


x=y

Then we can say that since
g\circ f f: A is an injective too ("one to one" ) function.

Prove that if f : A → B, g : B → C, and g ◦ f is injective , then f : A injective-example-1
User Samuel Hapak
by
6.1k points
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