Answer:
Find the upper base of this trapezoid:
15 + (5 + 5)
where 15 = the upper base of the rectangle
and 5 = the legs of the triangles
Solve:
15 + 5 + 5
= 25, is the length of the upper base.
The length below this trapezoid is already given, 15.
Now we find the hypotenuse of one triangle and double it, since there's two triangles that consist of the same lengths.
Using the Pythagoras theorem;
c^2 = a^2 + b^2
c^2 = 3^2 + 5^2
c^2 = 9 + 25
c^2 = 34
√34 = 5.83, is the hypotenuse of one triangle, two triangles is;
5.83 x 2 = 11.66, are the hypotenuse's of both triangles.
Now we add up all the lengths:-
25 + 15 + 11.66
= 51.66 cm