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Ageostationary satellite for communication seems to be in afixed spot above the equator because it has the same angular velocity as the earth? A.show that if it goes round once aday it is angular velocity w is alittle over 7×10power-5rad/s​

User Chandru
by
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2 Answers

3 votes

Answer: period=24hours=24*60*60s=86400s

1/period=1/86400=1.157*10*-5=Frequency

  • Explanation:Ф=2*π*Frequency

=628*1.157*10*-5=7.26*10*-5 as Frequency

User Bronumski
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4.1k points
9 votes

Answer:

w=2PI/time=2PI/1day*1day/24hrs*1hr/3600sec= 2PI/(24*3600)=

= 7.27220522e-5 rad/sec

User ZKSteffel
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3.9k points