Answer:
1/2^16 or 0.0000152588 microbes
Explanation:
Assuming you start with just one microbe that divides every 30 minutes.
This means that the half life of the microbe is 30 minutes or 0.5hours
The interpretation of this half life is that after every half-life, which in this case is 30 minutes, half of the microbe will be gone, and half will remain.
It follows that after another half hour the amount remaining will be
1/2 of 1/2= 1/4 microbes
Thus after 8 hours, there would have been (8/0.5)=16 half lives.
Therefore the amount of microbes remaining will be 1/2^16 of 1 = 0.0625
Alternatively, we could solve the differential equation
dM/dt=kM, where dM/dt is the rate of decay, and M is the amount at any time t, k is the decay constant
Solution of this first order differential equation by separating the variables and integrating yields {dM/M={kt+c, lnM=kt+c, and ......
M=Moexp(-kt)
The initial value Mo=1, when t=0, and given value M=0.5, t=0.5h yields the value of k as follows
0.5=exp(-k*0.5)
ln(0.5)=-k*0.5
k=1.386
After any time time, thus the given expression holds
M=exp(-1.386t)
Thus after 8 hours, the microbes remaining will be
M=exp(-1.386t)=exp(-1.386*8)=0.000152588 microbes.