1 Answer

An Phan · Answer 1 · 2021-10-24T08:30:37+0000

Answer:
(7)/(8)

Explanation:

Given : When a coin is tossed twice , the total outcomes will become

HHH , HHT , HTH , THH , TTH , THT , HTT ,TTT

Total outcomes = 8

Favorable outcomes to obtain 1 and 3 inclusive = HHT , HTH , THH , TTH , THT , HTT ,TTT

Number of favorable outcomes = 7

Probability that the number of tails obtained will be between 1 and 3 inclusive =
$\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

=(7)/(8)

Hence, the probability that the number of tails obtained will be between 1 and 3 inclusive

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