Question

The perimeter of a rectangle is 40 inches the width is 8 inches shorter than the length find the dimensions of the rectangle

Answer 1

p=40

w=l-8

40=w+l

40=2(l-8)+2l

40=2l-16+2l

40=4l-16

56=4l

14=l

length=14

w=14-8=6

l=14

w=6

Answer 2

Main equation:

2L + 2w = 40

We know that

w = L - 8

Substitute in known value

2L + 2(L - 8) = 40

Solve

2L + 2L - 16 = 40

4L = 24

L = 6

Length = 6 inches

Width = 14 inches

Hope this helps :)