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The sum of the first 200 terms of the arithmetic sequence with initial term 2 and common difference 3 is

A. 599B. 601C. 604D. 60100E. 60400

User Coryj
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1 Answer

4 votes

Answer: D. 60100

Explanation:

The formula for determining the sum of n terms of an arithmetic sequence is expressed as

Sn = n/2[2a + (n - 1)d]

Where

n represents the number of terms in the arithmetic sequence.

d represents the common difference of the terms in the arithmetic sequence.

a represents the first term of the arithmetic sequence.

From the information given,

n = 200 terms

a = 2

d = 3

Therefore, the sum of the first 200 terms, S200 would be

S200 = 200/2[2 × 2 + (200 - 1)3]

S200 = 100[4 + 597)

S200 = 100 × 601 = 60100

User Harold Castillo
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