Question

To make an effective buffer, 25.00 mL of 0.025 M HF should be mixed with ______mL of 0.050 M NaOH

Answer 1

Answer: The volume of NaOH will be, 12.5 mL

Step-by-step explanation:

To calculate the volume of base, we use the equation given by neutralization reaction:

`n_1M_1V_1=n_2M_2V_2`

where,

`n_1,M_1\text{ and }V_1` are the n-factor, molarity and volume of acid which is
`HF`

`n_2,M_2\text{ and }V_2` are the n-factor, molarity and volume of base which is NaOH.

We are given:

`n_1=1\\M_1=0.025M\\V_1=25.00mL\\n_2=1\\M_2=0.050M\\V_2=?`

Putting values in above equation, we get:

`1* 0.025M* 25.00mL=1* 0.050M* V_2\\\\V_2=12.5mL`

Hence, the volume of NaOH will be, 12.5 mL