Sound intensity (energy) falls inversely proportional to the square of the distance from the sound:
![I \propto (1)/(r^2)](https://img.qammunity.org/2021/formulas/physics/college/c8y6o2kl9za5j7c7yzowhykys8zb253mvc.png)
Therefore if we have two values of intensities we have
![(I_1)/(I_2) = (r_2^2)/(r_1^2)](https://img.qammunity.org/2021/formulas/physics/college/mdkfbccr0yg9zha63andjc48n7zbxhhrj8.png)
As we have that
![r_1 = 3 r_2](https://img.qammunity.org/2021/formulas/physics/college/oo53v3xj133wpngrs3ebx0003reub7iq3i.png)
Then we have that
![(I_1)/(I_2) = (r_2^2)/((3r_2)^2)](https://img.qammunity.org/2021/formulas/physics/college/sr2xtapv2de9yep626b68ofuqq2vajvvtk.png)
![(I_1)/(I_2) = (1)/(9)](https://img.qammunity.org/2021/formulas/physics/college/5hulqpdk27hsk31g8sekxsbywpion70wdv.png)
Therefore the correct answer is D. The sound intensity drops to 1 / 9 of its original value.