Question

Consider the voltaic cellZn(s) + Cu{2+}(aq)--> Zn{2+}(aq)+Cu(s){}=chargeUnder standard conditions, what is the maximum electrical work, in Joules that can accomplish if 60 g of copper is plated out?

Answer 1

Max. work done in 60 g of copper plated out is 200472.14 J

Step-by-step explanation:

Given cell reaction is:

`Zn(s)+Cu^(2+) \rightarrow Zn^(2+)+Cu(s)`

Standard reduction potential of Zn electrode (
`E_(Zn^(2+)/Zn)`) is 0.763 V.

Standard reduction potential of Cu electrode (
`E_(Cu^(2+)/Cu)`) is -0.337 V.

Copper acts as cathode and Zinc acts as anode.

Cell potential (E) = E° cathode - E° anode

= 0.763 - (-0.337)

= 1.10 V

formula for the work done is as follows:

`W_(max)=-nFE`

Here, n is no. of electron involved in the reaction.

F(Faraday's constant) = 96500

In the given reaction, n = 2

`W_(max)=-nFE\\=-2 *\ 96500 * 1.10\\=-212300\ J/mol`

Therefore, 212300 J work is done by reducting 1 mol of copper.

Copper given is 60 g.

Molecular mass of copper is 63.54 g/mol.

`No.\ of\ mol = (60\ g)/(63.54\ g/mol)`

Max. work done in 60 g of copper plated out is:

`W_(max)=212300\ J/mol * (60\ g)/(63.54\ g/mol) \\=200472.14\ J`