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Wire resistor A has twice the length and twice the cross sectional area of wire resistor B. Which of the following accurately compares the resistances of wire resistors A and B?a) Wire A has twice the resistance of wire B.b) Wire A has half the resistance of wire B.c) Wire A has the same resistance as wire B.d) None of the above

User Emacs User
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1 Answer

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Answer: Option (c) is the correct answer.

Step-by-step explanation:

It is known that the relation between resistance, length and cross-sectional area is as follows.

R =
\rho (l)/(A)

Let the resistance of resistor A is denoted by R and the resistance of resistor B is denoted by R'.

Hence, for resistor A the expression for resistance according to the given data is as follows.

R =
\rho (2l)/(2A)

On cancelling the common terms we get the expression as follows.

R =
\rho (l)/(A)

Now, the resistance for resistor B is as follows.

R' =
\rho (l')/(A')

Thus, we can conclude that the statement, Wire A has the same resistance as wire B, accurately compares the resistances of wire resistors A and B.

User George Rushby
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