Question

Alexander and Jo live 5 miles apart. They decide to leave their homes at 3 p.M. And travel toward each other. If Alexander bikes 14 miles per hour and Jo jogs 6 miles per hour, when will they meet?

Answer 1

Explanation:

Here is an illustration of the problem:

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A t J

Alex and Jo start from their separate homes and drive towards one another. The t indicates the time at which they meet, which is the same time for both. Filling in a d = rt table:

d = r x t

Alex 14 t

Jo 6 t

The formula for motion is d = rt, so that means that Alex's distance is 14t and Jo's distance is 6t.

14t 6t

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A t J

The distance between them is 5 miles, so that means that Alex's distance plus Jo's distance equals 5 miles. In equation form:

14t + 6t = 5 and

20t = 5 so

t = .25 hours or 15 minutes.

If they leave their homes at 3 and they meet 15 minutes later, then they meet at 3:15.