Question

In ΔABC, m∠ACB = 90°, CD ⊥ AB and m∠ACD = 45°. Find: AC, if CD = 6√2 in.

Answer 1

AC = 12 units.

Explanation:

Δ ACD is right-angled. ( as CD ⊥ AB).

cos 45° = CD / AC = 6√2 / AC

AC = 6√2 / cos 45°

AC = 6√2 / 1 /√2

= 6√2 *√2

= 6 * 2

= 12 (answer)

HOPE THIS HELPED ;3