Answer:
The answer is:
![(1)/(8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/hcxhwcun3tdhxxrdgcla5lb39my4jlljjt.png)
Explanation:
The sample space when tossing a coin three times is [HHH, HHT, HTH, HTT, THH, THT, TTH, TTT] and the total number of occurrence is 8.
Getting Head on first toss, tail on second and third is: HTT and it occurs just once in our sample space.
Therefore, the probability of getting Head on first toss, tails on second and third tosses is:
![(1)/(8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/hcxhwcun3tdhxxrdgcla5lb39my4jlljjt.png)
Note probability =
![(number of possible occurrence)/(number of total occurrence)](https://img.qammunity.org/2021/formulas/mathematics/high-school/2f15jc9vhnywq3z4pf3zdepf7bdpjm3vws.png)