Question

Find the zeros of the function in the interval [-2pi, 2pi] f(x)= -4sin x

Answer 1

It's B) 0, ±pi, ±2pi on edge

Answer 2

Zeros are
`x=-2\pi,-\pi,0,\pi,2\pi`

Explanation:

`f(x)=0\\-4\sin x=0\\\sin x=0\\`

`\sin(-2\pi)=0\\\sin(-\pi)=0\\\sin(0)=0\\\sin(\pi)=0\\\sin(2\pi)=0`