Question

If the magnitude of a positive charge is tripled, what is the ratio of the original value of the electric field at a point to the new value of the electric field at that same point?

a) 1:2
b) 1:3
c) 1:6
d) 1:9

Answer 1

b)1 :3

Step-by-step explanation:

Lets that

The value of a positive charge = q

As we know that electric filed on a point charge given as

`E=(Kq)/(r^2)`

Where ,K=Constant

q=Charge ,r=Distance

If the value of the charge gets tripled ,q'= 3 q

Then electric filed E'

`E'=(Kq')/(r^2)`

`E'=(3Kq)/(r^2)`

E' = 3 E

Therefore we can say that

`(E)/(E')==(1)/(3)`

therefore the answer will be --

b)1 :3