Question

Miriam is playing a game of dice. For every 1 or 6 rolled, Miriam will in $5. For any other number, she must pay $2. How much money can Miriam except to win or lose?

Answer 1

So, she can expect to win a total of $0.33 .

Explanation:

According to the question miriam will get 5$ when the dice will show 1 or 6 .

And also she will lose 2$ for any other number .

Now ,

Total number of favorable cases for winning of 5$ for the miriam are 2.

Total number of cases = 6.

Also,

Total number of cases in which she will lose money will be 4.

So, probability of win =
`(2)/(6)`.

Probability of loss =
`(4)/(6)`.

Thus ,

Total amount of money that she can expect to win =

`(2)/(6)`×5 -
`(4)/(6)`×2 =
`(1)/(3)`.

So, she can expect to win a total of $0.33 .