Question

Find the indicated probability. Round to three decimal places. The participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men and women. Among the last 11 participants there have been only 2 women. If participants are picked randomly, what is the probability of getting 2 or fewer women when 11 people are picked? 0.006 0.033 0.027 0.032

Answer 1

0.033

Explanation:

Use binomial probability:

P = nCr pʳ (1−p)ⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

Here, p = 0.5, q = 0.5, and n = 11.

We need to find P when r is 0, 1, and 2, then add up the results to get the total probability.

r = 0:

P = ₁₁C₀ (0.5)⁰ (0.5)¹¹⁻⁰

P ≈ 0.0005

r = 1:

P = ₁₁C₁ (0.5)¹ (0.5)¹¹⁻¹

P ≈ 0.0054

r = 2:

P = ₁₁C₂ (0.5)² (0.5)¹¹⁻²

P ≈ 0.0269

Therefore, the total probability is:

P = 0.0005 + 0.0054 + 0.0269

P = 0.0328

Round to the thousandths place, the probability is 0.033.