Question

Ali's starting salary at her new job is

$4,300. It is expected to increase by 32
each year. What will Ali's salary be in 10
years?

Answer 1

4630

Explanation:

32 is one year right?

So multiply

10x32=320 then add 4300+320

= 4630

Answer 2

663268.49

Explanation:

Time, t = 10 Initial salary

P = 41300 rate

r = 32

Final salary = P(1+r/100)^t = 41300(1+32/100)^10

`41300\left((1+32)/(100)\right)^(10)`

`\mathrm{Apply\:exponent\:rule}:\quad \left((a)/(b)\right)^c=(a^c)/(b^c)`

`\left((1+32)/(100)\right)^(10)=(\left(1+32\right)^(10))/(100^(10))`

`=41300\cdot (\left(1+32\right)^(10))/(100^(10))`

`\mathrm{Add\:the\:numbers:}\:1+32=33`

`=41300\cdot (33^(10))/(100^(10))`

`=(41300)/(1)\cdot (33^(10))/(100^(10))`

`\mathrm{Apply\:the\:fraction\:rule}:\quad (a)/(b)\cdot (c)/(d)=(a\:\cdot \:c)/(b\:\cdot \:d)`

`=(41300\cdot \:33^(10))/(1\cdot \:100^(10))`

`\mathrm{Apply\:rule}:\quad \:a\cdot 1=a`

`1\cdot \:100^(10)=100^(10)`

`=(41300\cdot \:33^(10))/(100^(10))`

`\mathrm{Factor\:the\:number:\:}\:41300=100\cdot \:413`

`=(100\cdot \:413\cdot \:33^(10))/(100^(10))`

`=(413\cdot \:33^(10))/(100^9)`

`=663268.48697974...`

`\mathrm{Round:}` 663268.49

~Lenvy~