Question

a skater increases her speed uniformly from 2.0 m/s to 10 m/s in 3.0s. what is the acceleratioon of the biker?

Answer 1

a= 2.667 m/s²

Step-by-step explanation:

Given that

Initial velocity ,u= 2 m/s

Final velocity ,v= 10 m/s

Time taken ,t= 3 s

As we know that

v = u + at

a=Acceleration ,u=Initial velocity ,v= Final velocity ,t=time

Now by putting the values in the above equation

v = u + at

10 = 2 + a x 3

8 = 3 a

`a=(8)/(3)\ m/s^2`

a= 2.667 m/s²

Therefore the acceleration of the biker will be 2.667 m/s²