Answer:
[1]=Z the set of integers
[1/2]= r is an odd integer
Explanation:
Denote by [a] the equivalence class of an element a.
We know that [a]=(x,a)∈R. Then
[1]=(x,1)∈R=x=x
=x=k∈Z={...,-2+1,-1+1,0+1,1+1,2+1,...}=Z
For the other class, we have
[1/2]=(x,1/2)∈R=x-1/2 is an integer=x-1/2=r for some r∈Z
=x=r∈Z={...,-2+1/2,-1+1/2,0+1/2,1+1/2,..}
={...,-3/2,-1/2,1/2,3/2,...}=r/2