Question

The emission of x rays can be described as an inverse photoelectric effect.

What is the potential difference through which an electron accelerates to produce x rays with a wavelength of 0.10 nm?

Answer 1

The potential difference through which an electron accelerates to produce x rays is
`1.24* 10^4\ volts`.

Step-by-step explanation:

It is given that,

Wavelength of the x -rays,
`\lambda=0.1\ nm=0.1* 10^(-9)\ m`

The energy of the x- rays is given by :

`E=(hc)/(\lambda)`

The energy of an electron in terms of potential difference is given by :

`E=eV`

So,

`(hc)/(\lambda)=eV`

V is the potential difference

e is the charge on electron

`V=(hc)/(e\lambda)`

`V=(6.63* 10^(-34)* 3* 10^8)/(1.6* 10^(-19)* 0.1* 10^(-9))`

V = 12431.25 volts

or

`V=1.24* 10^4\ volts`

So, the potential difference through which an electron accelerates to produce x rays is
`1.24* 10^4\ volts`. hence, this is the required solution.