Question

What is the equation of the line with m = 6 that goes through the point (1, 4)?

A. y – 4 = 6(x + 1)
B. y – 4 = 6(x – 1)
C. y + 4 = 6(x – 1)
D. y + 4 = 6(x + 1)

Answer 1

Since it's a line we are talking about linear equation of a form

`f(x)=mx+n`

where
`m` is slope and
`n` is y-intercept.

Our particular line has a form of

`f(x)=6x+n`

So we are missing the y-intercept.

To find y-intercept
`n` we insert the coordinates of point
`P(x,f(x))\to P(1,4)` and solve for
`n`

`</p><p>4=6\cdot1+n \\</p><p>n=-2</p><p>`

So the final form of the line is

`y=6x-2`

Or as offered in the answers

`y-4=6(x-1)`

The answer is B.

Hope this helps.

Answer 2

Answer: B) y-4=6(x-1)

Substitute the point into each equation

A: y-4=6(x+1)

4-4=6(1+1)

4-4=6+6

0=12

This is false so it is not the answer

B: y-4=6(x-1)

4-4=6(1-1)

4-4=6-6

0=0

This is true so this is the answer, but I will continue solving just to check

C: y+4=6(x-1)

4+4=6(1-1)

4+4=6-6

8=0

This is false so it is not the answer

D: y+4=6(x+1)

4+4=6(1+1)

4+4=6+6

8=12
This is not true so it is not the answer

Your answer becomes b, the only true equation! Hope this helps comment below for more questions :)