Answer:
(1)
(2)
![b = 11-8=3](https://img.qammunity.org/2021/formulas/mathematics/high-school/fo1hu85cqoygwco2029t55ahmtfdcymo54.png)
![f= 8-2(3) = 8-6 =2](https://img.qammunity.org/2021/formulas/mathematics/high-school/py52x0af9v3aw3pw68n3fp4ke5538dqskg.png)
Explanation:
For this case we can put some notation
Let b= dozen bagels and f= delivery fee
And for this case we know that "On Monday, they delivered two dozen bagels, b, to an office at a total cost of $8", so then the total taling in count the delivery fee we have this:
![2b+f = 8](https://img.qammunity.org/2021/formulas/mathematics/high-school/mq70656bgnxl2vk2h5smom7qipdms11om9.png)
And for the other part "On Tuesday, three dozen bagels were delivered at a total cost of $11", we can write the expression like this:
![3b+f=11](https://img.qammunity.org/2021/formulas/mathematics/high-school/55actclr582k44y19bbqg33fkhe343oqfk.png)
And our system of equations would be:
(1)
(2)
If we solve for f from equation (1) we got:
![f= 8-2b](https://img.qammunity.org/2021/formulas/mathematics/high-school/81ldzyf3lq3637hkn4ipmjs6cz6saps62c.png)
And if w replace this into equation (2) we got:
![b = 11-8=3](https://img.qammunity.org/2021/formulas/mathematics/high-school/fo1hu85cqoygwco2029t55ahmtfdcymo54.png)
And solving for f we got:
![f= 8-2(3) = 8-6 =2](https://img.qammunity.org/2021/formulas/mathematics/high-school/py52x0af9v3aw3pw68n3fp4ke5538dqskg.png)