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Find the whole number such that twice its square subtracted from 7 time makes 3​

1 Answer

7 votes

Explanation:

Let the whole number be ‘n'

Twice it's square subtracted from 7 times the number makes 3 .

So,

7n - 2n^2 = 3

2n^2 - 7n = -3

2n^2 - 7n + 3 = 0

Factorising the above expression as,

2n^2 - 6n -n +3 =0

2n(n - 3) - 1(n - 3) =0

(n - 3) (2n - 1) = 0

(n - 3) =0 or (2n - 1) = 0

n - 3 =0 or 2n - 1 = 0

n = 3 or 2n = 1

n = 3 or n = 1/2

Since n is a whole number, the value of n must be 3.

The value of the whole number n = 3

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