173k views
5 votes
Find the whole number such that twice its square subtracted from 7 time makes 3​

1 Answer

7 votes

Explanation:

Let the whole number be ‘n'

Twice it's square subtracted from 7 times the number makes 3 .

So,

7n - 2n^2 = 3

2n^2 - 7n = -3

2n^2 - 7n + 3 = 0

Factorising the above expression as,

2n^2 - 6n -n +3 =0

2n(n - 3) - 1(n - 3) =0

(n - 3) (2n - 1) = 0

(n - 3) =0 or (2n - 1) = 0

n - 3 =0 or 2n - 1 = 0

n = 3 or 2n = 1

n = 3 or n = 1/2

Since n is a whole number, the value of n must be 3.

The value of the whole number n = 3

User Ashur
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories