Question

what are the charge and the charge density on the surface of a conducting sphere of radius 0.15 m whose potantial is 200v?

Answer 1

The charge and the charge density on the surface of a conducting sphere is
`3.34* 10^(-9)\ C` and
`1.18* 10^(-8)\ C/m^2` respectively.

Step-by-step explanation:

It is given that,

Radius of the conducting sphere, r = 0.15 m

Potential, V = 200 V

Potential on the surface of sphere is given by :

`V=(kq)/(r)`

q is the charge on the sphere

`q=(Vr)/(k)`

`q=(200* 0.15)/(9* 10^9)`

`q=3.34* 10^(-9)\ C`

Charge per unit area is called charge density on the surface. it is given by :

`\sigma=(q)/(A)`

`\sigma=(q)/(4\pi r^2)`

`\sigma=(3.34* 10^(-9))/(4\pi (0.15)^2)`

`\sigma=1.18* 10^(-8)\ C/m^2`

So, the charge and the charge density on the surface of a conducting sphere is
`3.34* 10^(-9)\ C` and
`1.18* 10^(-8)\ C/m^2` respectively. Hence, this is the required solution.