Solve for y in terms of x: 4 {x}^(2) + 8 {x}^(2)y = 8 {x}^(3) A. (2)/(2x - 1) B. (2)/(2x + 1) C. (2x - 1)/(2) D. (2)/(2x - 1)

asked Sep 10, 2021 133k views

0 votes

Solve for y in terms of x:

$4 {x}^(2) + 8 {x}^(2)y = 8 {x}^(3)$
A.

(2)/(2x - 1)

$Solve for y in terms of x: 4 {x}^(2) + 8 {x}^(2)y = 8 {x}^(3) A. (2)/(2x - 1) B. (2)/(2x-example-1$

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7 votes

Answer:

8x^2y= 8x^3 - 4x^2

y = x - 1/2

y = (2x - 1)/2

the answer is c

DramboHero answered Sep 14, 2021

3.6k points

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