The bearing of A from B according to the diagram is 82.86°
Using trigonometric relations ;
- Tan B = opposite/ Adjacent
B = bearing of A from B
Now we have;
Tan B = 40 /5
Tan B = 8
Take the inverse value of the tangent ;
![B = Tan^(-1) (8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ojo2zjuneeu1e63u35ivf2bisz0mq6rvjj.png)
B = 82.86°
Hence, the bearing of A from B is 82.86°