Question

Struggling un this section

Answer 1

`10`

Explanation:

Combinations : When there are total
`n` choices and you have to choose
`k`of them (in any order)

The possible ways
`= \ ^n{c_(k)} = (n!)/(k!(n-k)!)`

Here total chances
`=5`

and we have to choose
`2`of them.

Possible ways
`=\ ^5{c_(2)}`

`=&(5!)/(2!(5-2)!) = (5!)/(3! 2!) \\\\=&(5 * 4* 3!)/(3! 2!) = (5 * 4)/(2) = 10`