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4 votes
Solve triangle ABC

c = 10, B = 35°, C = 65°

Question options: A = 80°, a = 10, b = 6.3

A = 80°, a = 6.3, b = 10.9

A = 80°, a = 10.9, b = 6.3

A = 80°, a = 73.6, b = 6.3

Solve triangle ABC c = 10, B = 35°, C = 65° Question options: A = 80°, a = 10, b = 6.3 A-example-1
User Techflash
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1 Answer

4 votes

That figure obviously doesn't go with this problem. It doesn't matter; this is triangle ABC labeled the usual way.

c = 10, B = 35°, C = 65°

We have two angles and a side. The third angle is obviously

A = 180° - 35°- 65° = 80°

The remaining sides are given by the Law of Sines,


(a)/(\sin A)=(b)/(\sin B)=(c)/(\sin C)


a = (c \sin A)/(\sin C) = (10 \sin 80)/(\sin 65) = 10.866


b = (c \sin B)/(\sin C) = (10 \sin 35)/(\sin 65) = 6.328

Answer: A=80°, a=10.9, b=6.3, third choice

User CLaRGe
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