Question

how many grams of aspartame(c14h18n2o5), also known as nutrasweet, are contained in 45.0ml of a 0.250m solution?

Answer 1

3.3075 g

Step-by-step explanation:

In order to find the mass of aspartame, we must:

1. Find the number of moles of aspartame
2. Find the Mr [molecular mass] of aspartame

We can find the number of moles from the concentration and volume of solution given, with the aid of the formula:

Number of moles = Concentration × Volume

Concentration= 0.250M

Volume= 45.0 ml = 0.045 dm³

Number of moles =0.25 × 0.045 = 0.01125 mol

Now, we have to find the Mr of aspartame.

Mr of C₁₄H₁₈N₂O₅ = (12 × 14) + (1 × 18) × (14 × 2) + (16 ×5) = 294

Thus we can find the mass using the formula:

Mass = Number of moles × Mr

Mass = 0.01125 × 294 = 3.3075 g