Question

A bag contains one red pen, four black pens, and three blue pens. Two pens are randomly chosen from the bag and are not replaced. To the nearest hundredth, what is the probability that a black pen is chosen first and then another black pen is chosen?.

Answer 1

o.21

Explanation:

edge 22

Answer 2

3/14

Explanation:

total pens = one + four + three = 1 + 4 + 3 = 8

there are 4 black pens

probability a black pen is chosen randomly: 4/8 (number of outcomes/total outcomes) = 1/2

take the pen out

there are now 3 black pens and 8-1 = 7 total pens

probability a black pen is now chosen: 3/7

we want to find the probability that the black pen is chosen first AND second at random.

P(A and B) = P(A) * P(B)

multiply the 2 probabilities to get our solution

1/2 * 3/7 = 3/14