Question

Hey Guys !!!!

pls Help me out.....


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Answer 1

D)
`3m + 21`

Explanation:

We know that the average is a value divided by 2: So we can calculate the average in terms of x:

We know that:

`x = m + 9`

`y = 2m + 15`

`z = 3m + 18`

To find the average of x, y, z we can add them then we can divide by 2 to find the average in terms of m:

`m + 9 + 2m + 15 + 3m + 18 = 6m + 42`

I have combined like terms and then using that I can divide this by 2:

`6m + 42 / 2 = 3m + 21`

Answer 2

Hey There!

Let's solve...

First we need to find out the equation of x which is

`x = (m + 9)/(2) \\`

Now let's find out the equation of y which is

`y = (2m + 15)/(2) \\`

Now let's find out equation of z which is

`z = (3m + 18)/(2) \\`

On adding the three equations, we get

`2x + 2y + 2z = m + 2m + 3m + 9 + 15 + 18`

Now we get..

`2(x + y + z) = 6m + 42 \\ \\ x + y + z = 3m + 21`

Now let's find our the average of x,y snd z which is

`(x + y + z)/(3) \\ which \: is \: \\ \\ (3m + 21)/(3)`

`now \: factor \: 3m + 21 \: which \\ is \: 3(m + 7)`

Now simplify..

`\frac{ \cancel{3}(m + 7)}{ \cancel{3}} \\`

So answer is m+7

I hope it is helpful to you..

Cheers!____________