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I Dont know how to do this can someone pls help

I Dont know how to do this can someone pls help-example-1

1 Answer

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Answer: The "41-80" interval

Step-by-step explanation:

Look at the bottom row of the table. The total cumulative frequency is 31 which tells us there are 31 data items in this set. The median is at slot 16 because 31/2 = 15.5 which rounds up to 16. Imagine a list of 31 items. The first 15 are below the median while the final 15 are above the median. We have 15+1+15 = 31 items total.

We compare that 16 to the cumulative frequencies mentioned. What we're looking for is the closest cumulative frequency that's above 16. That would be the 19. This places the median somewhere in the "41-80" interval in row 4. We unfortunately don't have enough info to pin down the exact median value.

Side note: Because a lot of values are at the far right side of the list, this makes the distribution left-skewed (aka negatively skewed) because of the outliers to the left. Furthermore, it indicates the arithmetic mean is smaller than the median.

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