Question

Consider the reaction between NiS2 and O2:

2NiS2(s)+5O2(g)→2NiO(s)+4SO2(g) When 11.2 g of NiS2 are allowed to react with 5.43 g of O2, 4.29 g of NiO are obtained.

Determine the theoretical yield of NiO for the reaction.

Determine the percent yield for the reaction.

Answer 1

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Dejanras

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m(NiS₂) = 11.2 g.

n(NiS₂) = m(NiS₂) ÷ M(NiS₂).

n(NiS₂) = 11.2 g ÷ 122.8 g/mol.

n(NiS₂) = 0.091 mol.

m(O₂) = 5.43 g.

n(O₂) = 5.43 g ÷ 32 g/mol.

n(O₂) = 0.17 mol; limiting reactant.

From chemical reaction: n(NiS₂) : n(O₂) = 2 : 5.

0.091 mol : n(O₂) = 2 : 5.

n(O₂) = 0.2275 mol, not enough.

n(NiO) = 4.89 g .

n(O₂) : n(NiS) = 5 : 2.

n(NiS) = 0.068 mol.

m(NiS) = 0.068 mol · 74.7 g/mol = 5.08 g.

percent yield = 4.89 g / 5.08 g · 100% = 96.2%.