Question

A sequence starts from -2. The term to term rule is 'square and subtract 3' find the first six numbers of the sequence

Answer 1

The first six numbers are
`-2,1,-2,1,-2,1`

Explanation:

First term is
`-2`

The term to term rule is 'square and subtract
`3`'

Second term
`=(-2)^(2) -3=1`

Third term
`=(1)^(2) -3=-2`

Fourth term
`=(-2)^(2) -3=1`

Fifth term
`=(1)^(2) -3=-2`

Sixth term
`=(-2)^(2) -3=1`

The first six numbers are
`-2,1,-2,1,-2,1`