Question

What is the solution for x^0.5logx=0.01x^2 ?

Answer 1

x1= 100 x2=99.999

Explanation:

`x^{0.5\log _(10)\left(x\right)}=0.01x^2`

`0.5\log _(10)\left(x\right)\log _(10)\left(x\right)=\log _(10)\left(0.01\right)+2\log _(10)\left(x\right)`

u=log(x)

`0.5uu=\log _(10)\left(0.01\right)+2u`

`u=2+√(1.0E-15),\:u=2-√(1.0E-15)`

`x=10^(2+√(1.0E-15)),\:x=10^(2-√(1.0E-15))`